`continue`

continue se usa dentro de la estructura del bucle para saltar el resto de la iteraciÃ³n actual del bucle y continuar la ejecuciÃ³n al comienzo de la siguiente iteraciÃ³n.

Nota: Tener en cuenta que en PHP la declaraciÃ³n switch es considerada una estructura de bucle por continue.

continue accepta un parÃ¡metro opcional, el cual determina cuantos niveles (bluces) hay que saltar antes de continuar con la ejecuciÃ³n.


<?php

while (list ($key, $value) = each ($arr)) {

    if (!($key % 2)) { // skip odd members

        continue;

    }

    do_something_odd ($value);

}



$i = 0;

while ($i++ < 5) {

    echo "Outer<br>\n";

    while (1) {

        echo "&nbsp;&nbsp;Middle<br>\n";

        while (1) {

            echo "&nbsp;&nbsp;Inner<br>\n";

            continue 3;

        }

        echo "Esto nunca se imprime.<br>\n";

    }

    echo "Y esto tampoco.<br>\n";

}

?>

add a note User Contributed Notes
continue

szrrya at yahoo dot com
17-Jul-2006 02:18


Documentation states:



"continue is used within looping structures to skip the rest of the current loop iteration"



Current functionality treats switch structures as looping in regards to continue.  It has the same effect as break.



The following code is an example:



<?php

for ($i1 = 0; $i1 < 2; $i1++) {

  // Loop 1.

  for ($i2 = 0; $i2 < 2; $i2++) {

    // Loop 2.

    switch ($i2 % 2) {

      case 0:

        continue;

        break;

    }

    print '[' . $i2 . ']<br>';

  }

  print $i1 . '<br>';

}

?>



This outputs the following:

[0]

[1]

0

[0]

[1]

1



Switch is documented as a block of if...elseif... statements, so you might expect the following output:

[1]

0

[1]

1



This output requires you to either change the switch to an if or use the numerical argument and treat the switch as one loop.

Rene
18-Feb-2006 12:24


(only) the reason that is given on the "Continue with missing semikolon" example is wrong.



the script will output "2" because the missing semikolon causes that the "print"-call is executed only if the "if" statement is true. It has nothing to to with "what" the "print"-call would return or not return, but the returning value can cause to skip to the end of higher level Loops if any call is used that will return a bigger number than 1.



<?php

continue print "$i\n";

?>



because of the optional argument, the script will not run into a "unexpected T_PRINT" error. It will not run into an error, too, if the call after continue does return anything but a number.



i suggest to change it from:

because the return value of the print() call is int(1), and it will look like the optional numeric argument mentioned above.



to

because the print() call will look like the optional numeric argument mentioned above.

net_navard at yahoo dot com
25-Dec-2005 09:01


Hello firends



It is said in manually:

continue also accepts an optional numeric argument which tells it how many levels of enclosing loops it should .



In order to understand better this,An example for that:

<?php



/*continue also accepts an optional numeric argument which 

    tells it how many levels of enclosing loops it should skip.*/



for($k=0;$k<2;$k++)

{//First loop



    

    for($j=0;$j<2;$j++)

    {//Second loop



      for($i=0;$i<4;$i++)

      {//Third loop

    if($i>2)

    continue 2;// If $i >2 ,Then it skips to the Second loop(level 2),And starts the next step,

    echo "$i\n";

       }



    }



}



?>



Merry's christmas :)

    

With regards,Hossein

dedlfix gives me a hint
28-Jan-2005 06:47


a possible solution for 

greg AT laundrymat.tv



I've got the same problem as Greg

and now it works very fine by using

return() instead of continue.



It seems, that you have to use return()

if you have a file included and

you want to continue with the next loop

greg AT laundrymat.tv
14-Jan-2005 08:58


You using continue in a file included in a loop will produce an error.  For example:



//page1.php

for($x=0;$x<10;$x++)

   {

    include('page2.php');    

}



//page2.php



if($x==5)

    continue;

else 

   print $x;



it should print



"012346789" no five, but it produces an error:



Cannot break/continue 1 level in etc.

www.derosetechnologies.com
10-May-2004 08:58


In the same way that one can append a number to the end of a break statement to indicate the "loop" level upon which one wishes to 'break' , one can append a number to the end of a 'continue' statement to acheive the same goal. Here's a quick example:



<?

    for ($i = 0;$i<3;$i++) {

        echo "Start Of I loop\n";

        for ($j=0;;$j++) {

            

            if ($j >= 2) continue 2; // This "continue" applies to the "$i" loop 

            echo "I : $i J : $j"."\n";

        }

        echo "End\n";

    }

?>



The output here is:

Start Of I loop

I : 0 J : 0

I : 0 J : 1

Start Of I loop

I : 1 J : 0

I : 1 J : 1

Start Of I loop

I : 2 J : 0

I : 2 J : 1



For more information, see the php manual's entry for the 'break' statement.

CelloG at phpdoc dot org
01-May-2003 06:55


continue works for:



do

while

switch

for

foreach

add a note

MANUAL DE PHP

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`continue`