CapÃtulo 12. Variables

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Conceptos BÃ¡sicos
Variables predefinidas
Ambito de las variables
Variables variables
Variables externas a PHP

Conceptos BÃ¡sicos

En PHP las variables se representan como un signo de dÃ³lar seguido por el nombre de la variable. El nombre de la variable es sensible a minÃºsculas y mayÃºsculas.

Los nombres de variables siguen las mismas reglas que otras etiquetas en PHP. Un nombre de variable valido tiene que empezar con una letra o una raya (underscore), seguido de cualquier nÃºmero de letras, nÃºmeros y rayas. Como expresiÃ³n regular se podria expresar como: '[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'

Nota: En nuestro caso, una letra es a-z, A-Z, y los caracteres ASCII del 127 al 255 (0x7f-0xff).


<?php

$var = "Bob";

$Var = "Joe";

echo "$var, $Var";      // outputs "Bob, Joe"



$4site = 'not yet';     // invalid; starts with a number

$_4site = 'not yet';    // valid; starts with an underscore

$tÃ¤yte = 'mansikka';    // valid; 'Ã¤' is ASCII 228 (Extendido)

?>

En PHP3, las variables siempre se asignan por valor. Esto significa que cuando se asigna una expresiÃ³n a una variable, el valor Ãntegro de la expresiÃ³n original se copia en la variable de destino. Esto quiere decir que, por ejemplo, despuÃ©s e asignar el valor de una variable a otra, los cambios que se efectÃºen a una de esas variables no afectarÃ¡ a la otra. Para mÃ¡s informaciÃ³n sobre este tipo de asignaciÃ³n, vea Expresiones.

PHP4 ofrece otra forma de asignar valores a las variables: asignar por referencia. Esto significa que la nueva variable simplemente referencia (en otras palabras, "se convierte en un alias de" Ã³ "apunta a") la variable original. Los cambios a la nueva variable afectan a la original, y viceversa. Esto tambiÃ©n significa que no se produce una copia de valores; por tanto, la asignaciÃ³n ocurre mÃ¡s rÃ¡pidamente. De cualquier forma, cualquier incremento de velocidad se notarÃ¡ sÃ³lo en los bucles crÃticos cuando se asignen grandes matrices u objetos.

Para asignar por referencia, simplemente se antepone un ampersandsigno "&" al comienzo de la variable cuyo valor se estÃ¡ asignando (la variable fuente). Por ejemplo, el siguiente trozo de cÃ³digo produce la salida 'Mi nombre es Bob' dos veces:


<?php

$foo = 'Bob';              // Asigna el valor 'Bob' a $foo

$bar = &amp;$foo;              // Referencia $foo v&iacute;a $bar.

$bar = "Mi nombre es $bar";  // Modifica $bar...

echo $foo;                 // $foo tambi&eacute;n se modifica.

echo $bar;

?>

Algo importante a tener en cuenta es que sÃ³lo las variables con nombre pueden ser asignadas por referencia.


<?php

$foo = 25;

$bar = &amp;$foo;      // Esta es una asignaci&oacute;n v&aacute;lida.

$bar = &amp;(24 * 7);  // Inv&aacute;lida; referencia una expresi&oacute;n sin nombre.



function test() {

   return 25;

}



$bar = &amp;test();    // Inv&aacute;lida.

?>

add a note User Contributed Notes
Variables

giunta dot gaetano at sea-aeroportimilano dot it
04-Aug-2006 01:44


With php 5.1.4 (and maybe earlier?) take care about not using $this as a variable name, even when in the global scope or inside a plain function: the engine will prevent assigning any value to it...

molnaromatic at gmail dot com
20-May-2006 05:44


Simple sample and variables and html "templates":

The PHP code:

variables.php:

<?php

$SYSN["title"] = "This is Magic!";

$SYSN["HEADLINE"] = "Ez magyarul van"; // This is hungarian

$SYSN["FEAR"] = "Bell in my heart";

?>



http://indices.com.es/index.html:

<?php

include("variables.php");

include("template.html");

?>



The template:

template.html



<html>

<head><title><?=$SYSN["title"]?></title></head>

<body>

<H1><?=$SYSN["HEADLINE"]?></H1>

<p><?=$SYSN["FEAR"]?></p>

</body>

</html>

This is simple, quick and very flexibile

warhog at warhog dot net
27-Dec-2005 11:11


> Variable names follow the same rules as other labels in PHP. A valid variable name starts with a letter or underscore, followed by any number of letters, numbers, or underscores. As a regular expression, it would be expressed thus: '[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'



..is not quite true. You can, in fact, only declare variables having a name like this if you use the syntax <?php $varname = "naks naks"; ?>.. but in fact a variable can have moreless any name that is a string... e.g. if you look at an array you can have

<?php

$arr[''];

$arr['8'];

$arr['-my-element-is-so-pretty-useless-'];

?>

.. by accessing the variables-namespace via {} you can have the same functinalities for all variables, e.g.



<?php ${''} = "my empty variable"; ?>



is a valid expression and the variable having the empty string as name will have the value "my empty variable".



read the chapter on "variable variables" for further information.

Mike at ImmortalSoFar dot com
25-Nov-2005 02:03


References and "return" can be flakey:



<?php

//  This only returns a copy, despite the dereferencing in the function definition

function &GetLogin ()

{

    return $_SESSION['Login'];

}



//  This gives a syntax error

function &GetLogin ()

{

    return &$_SESSION['Login'];

}



//  This works

function &GetLogin ()

{

    $ret = &$_SESSION['Login'];

    return $ret;

}

?>

david at removethisbit dot futuresbright dot com
10-Nov-2005 01:25


When using variable variables this is invalid:



$my_variable_{$type}_name = true;



to get around this do something like:



$n="my_variable_{$type}_name";

${$n} = true;



(or $$n - I tend to use curly brackets out of habit as it helps t reduce bugs ...)

ludvig dot ericson at gmail dot com
13-Oct-2005 04:33


On the previous note:



This is due to how evaluation works. PHP will think of it as:



$a = whatever $b = $c is

$b = whatever $c = 1 is



... because an expression is equal to what it returns.



Therefore $c = 1 returns 1, making $b = $c same as $b = 1, which makes $b 1, which makes $a be $b, which is 1.



$a = ($b = $c = 1) + 2;

Will have $a be 3 while $b and $c is 1.



Hope that clears something up.

Chris Hester
31-Aug-2005 05:09


Variables can also be assigned together.



<?php

$a = $b = $c = 1;

echo $a.$b.$c;

?>



This outputs 111.

Mike Fotes
09-Jul-2005 11:46


In conditional assignment of variables, be careful because the strings may take over the value of the variable if you do something like this:



<?php

$condition = true;



// Outputs " <-- That should say test"

echo "test" . ($condition) ? " <-- That should say test" : "";

?>



You will need to enclose the conditional statement and assignments in parenthesis to have it work correctly:



<?php

$condition = true;



// Outputs "test <-- That should say test"

echo "test" . (($condition) ? " <-- That should say test " : "");

?>

josh at PraxisStudios dot com
17-May-2005 01:06


As with echo, you can define a variable like this:



<?php



$text = <<<END



<table>

    <tr>

        <td>

             $outputdata

        </td>

     </tr>

</table>



END;



?>



The closing END; must be on a line by itself (no whitespace).

user at host dot network
01-May-2005 05:17


pay attention using spaces, dots and parenthesis in case kinda like..

$var=($number>0)?1.'parse error':0.'here too';

the correct form is..

$var=($number>0)?1 .'parse error':0 .'here too';

or

$var=($number>0)?(1).'parse error':(0).'here too';

or

$var = ($number > 0) ? 1 . 'parse error' : 0 . 'here too';

etc..

i think that's why the parser read 1. and 0. like decimal numbers not correctly written, point of fact

$var=$number>0?1.0.'parse error':0.0.'here too';

seems to work correctly..

david at rayninfo dot co dot uk
25-Apr-2005 04:01


When constructing strings from text and variables you can use curly braces to "demarcate" variables from any surrounding text where, for whatever reason, you cannot use a space eg:



$str="Hi my name is ${bold}$name bla-bla";



which AFAIK is the same as 



$str="Hi my name is {$bold}$name bla-bla";



zzapper

mike at go dot online dot pt
07-Apr-2005 09:18


In addition to what jospape at hotmail dot com and ringo78 at xs4all dot nl wrote, here's the sintax for arrays:



<?php

//considering 2 arrays

$foo1 = array ("a", "b", "c");

$foo2 = array ("d", "e", "f");



//and 2 variables that hold integers

$num = 1;

$cell = 2;



echo ${foo.$num}[$cell]; // outputs "c"



$num = 2;

$cell = 0;



echo ${foo.$num}[$cell]; // outputs "d"

?>

lucas dot karisny at linuxmail dot org
14-Feb-2005 04:42


Here's a function to get the name of a given variable.  Explanation and examples below.



<?php

  function vname(&$var, $scope=false, $prefix='unique', $suffix='value')

  {

    if($scope) $vals = $scope;

    else      $vals = $GLOBALS;

    $old = $var;

    $var = $new = $prefix.rand().$suffix;

    $vname = FALSE;

    foreach($vals as $key => $val) {

      if($val === $new) $vname = $key;

    }

    $var = $old;

    return $vname;

  }

?>



Explanation:



The problem with figuring out what value is what key in that variables scope is that several variables might have the same value.  To remedy this, the variable is passed by reference and its value is then modified to a random value to make sure there will be a unique match.  Then we loop through the scope the variable is contained in and when there is a match of our modified value, we can grab the correct key.



Examples:



1.  Use of a variable contained in the global scope (default):

<?php

  $my_global_variable = "My global string.";

  echo vname($my_global_variable); // Outputs:  my_global_variable

?>



2.  Use of a local variable:

<?php

  function my_local_func()

  {

    $my_local_variable = "My local string.";

    return vname($my_local_variable, get_defined_vars());

  }

  echo my_local_func(); // Outputs: my_local_variable

?>



3.  Use of an object property:

<?php

  class myclass

  {

    public function __constructor()

    {

      $this->my_object_property = "My object property  string.";

    }

  }

  $obj = new myclass;

  echo vname($obj->my_object_property, $obj); // Outputs: my_object_property

?>

jospape at hotmail dot com
04-Feb-2005 11:45


$id = 2;

$cube_2 = "Test";



echo ${cube_.$id};



// will output: Test

ringo78 at xs4all dot nl
14-Jan-2005 12:27


<?

// I am beginning to like curly braces.

// I hope this helps for you work with them

$filename0="k";

$filename1="kl";

$filename2="klm";

 $i=0;

for ($varname = sprintf("filename%d",$i);   isset  ( ${$varname} ) ;   $varname = sprintf("filename%d", $i)  )  { 

    echo "${$varname} <br>";

    $varname = sprintf("filename%d",$i);

    $i++;

}

?>

Carel Solomon
07-Jan-2005 03:02


You can also construct a variable name by concatenating two different variables, such as:



<?



$arg = "foo";

$val = "bar";



//${$arg$val} = "in valid";     // Invalid

${$arg . $val} = "working";



echo $foobar;     // "working";

//echo $arg$val;         // Invalid

//echo ${$arg$val};     // Invalid

echo ${$arg . $val};    // "working"



?>



Carel

raja shahed at christine nothdurfter dot com
25-May-2004 10:58


<?php

error_reporting(E_ALL);



$name = "Christine_Nothdurfter";

// not Christine Nothdurfter

// you are not allowed to leave a space inside a variable name ;)

$$name = "'s students of Tyrolean language ";



print " $name{$$name}<br>";

print  "$name$Christine_Nothdurfter";

// same

?>

webmaster at surrealwebs dot com
09-Mar-2004 12:31


OK how about a practicle use for this:



You have a session variable such as:

$_SESSION["foo"] = "bar"

and you want to reference it to change it alot throughout the program instaed of typing the whole thing over and over just type this:



$sess =& $_SESSION

$sess['foo'] = bar;



echo $sess['foo'] // returns bar

echo $_SESSION["foo"] // also returns bar

just saves alot of time in the long run



also try $get = $HTTP_GET_VARS

or $post = $HTTP_POST_VARS

webmaster at daersys dot net
20-Jan-2004 08:15


In reference to "remco at clickbizz dot nl"'s note I would like to add that you don't necessarily have to escape the dollar-sign before a variable if you want to output it's name.



You can use single quotes instead of double quotes, too.



For instance:



<?php

$var = "test";



echo "$var"; // Will output the string "test"



echo "\$var"; // Will output the string "$var"



echo '$var'; // Will do the exact same thing as the previous line

?>



Why?

Well, the reason for this is that the PHP Parser will not attempt to parse strings encapsulated in single quotes (as opposed to strings within double quotes) and therefore outputs exactly what it's being fed with :)



To output the value of a variable within a single-quote-encapsulated string you'll have to use something along the lines of the following code:



<?php

$var = 'test';

/*

Using single quotes here seeing as I don't need the parser to actually parse the content of this variable but merely treat it as an ordinary string

*/



echo '$var = "' . $var . '"';

/*

Will output:

$var = "test"

*/

?>



HTH

- Daerion

unleaded at nospam dot unleadedonline dot net
14-Jan-2003 06:37


References are great if you want to point to a variable which you don't quite know the value yet ;)



eg:



$error_msg = &$messages['login_error']; // Create a reference



$messages['login_error'] = 'test'; // Then later on set the referenced value



echo $error_msg; // echo the 'referenced value'



The output will be:



test

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MANUAL DE PHP

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CapÃtulo 12. Variables

Conceptos BÃ¡sicos

MANUAL DE PHP

windsurf mercedes camper

CapÃ­tulo 12. Variables

Conceptos BÃ¡sicos

CapÃtulo 12. Variables